6.12: Chapter 8 Solution (Practice + Homework)
- Page ID
- 51819
Figure \(\PageIndex{23}\)
136.
- \(\overline x = $568,873\)
- \(CL = 0.95\) \(\alpha = 1 – 0.95 = 0.05\) \(z_{\frac{\alpha}{2}}=1.96\)
\(E B M=z_{0.025} \frac{\sigma}{\sqrt{n}}=1.96 \frac{909200}{\sqrt{40}}=\$ 281,764\) - \(\overline x − EBM = 568,873 − 281,764 = 287,109\)
\(\overline x + EBM = 568,873 + 281,764 = 850,637\) - We estimate with 95% confidence that the mean amount of contributions received from all individuals by House candidates is between $287,109 and $850,637.
139.
Higher
140.
It would increase to four times the prior value.
141.
No, It could have no affect if it were to change to \(1 – p\), for example. If it gets closer to 0.5 the minimum sample size would increase.
142.
Yes
143.
- No
- No